#### Hint

Consider the figures that complement the given 100 figures to complete the square.

#### Solution

Denote the given 100 figures as $A_{1}$, $A_{2}$,…, $A_{100}$, and their areas as $S_{1}$, $S_{2}$,…, $S_{100}$, respectively. By the condition, $S_{1}$ + $S_{2}$ + … + $S_{100}$$<$99. Let us denote by $B_{i}$ a figure that complements the figure $A_{i}$ to complete the square $($that is, it consists of all points of the square that do not belong to the figure $A_{i}$$)$. Then the area of the figure $B_{i}$ is 1-$S_{i}$ $($for i = 1,2,..., 100$)$. Then the sum of the areas of the figures $B_{1}$, $B_{2}$, ..., $B_{100}$ is $($1-$S_{1}$$)$ + $($1-$S_{2}$$)$ + ... + $($1-$S_{100}$$)$ = 100 - $($$S_{1}$ + $S_{2}$ + ... + $S_{100}$$)$, which is less than 1. So, the sum of the areas of the figures $B_{1}$, $B_{2}$,..., $B_{100}$ is less than the area of the square. This means that there is a point in the square that does not belong to one of the figures $B_{1}$, $B_{2}$,..., $B_{100}$. Therefore, this point belongs to each of the figures $A_{1}$, $A_{2}$,..., $A_{100}$.